![]() ![]() The probability of the third coin to land on a tail = The probability of the second coin to land on a tail = The probability of the first coin to land on a tail = The tree diagram of three coins rolled simultaneously is shown below: Draw a tree diagram and calculate the probability of three coins landing on Hence, there is a 45% chance of selecting 2 girls and a boy from a class of 20 students. Probability of selecting 2 boys and a girl = 0.15 + 0.15 + 0.15 There are three scenarios if the group contains 2 girls and a boy. Hence, there is a 29.4% chance of selecting 2 boys and a girl from a class of 20 students. Probability of selecting 2 boys and a girl = 0.098 + 0.098 + 0.098 Probability of selecting the first girl = Probability of selecting a boy, a girl and then a boy = Probability of selecting 2 boys and a girl = Probability of selecting the second boy = We will calculate the probabilities of each of these scenarios separately like this: There are three scenarios if the group contains 2 boys and a girl. Hence, there is a 19.2% chance of selecting all three girls at random in a group. Probability of selecting three girls at random = Probability of selecting the third girl = Probability of selecting the second girl = Total number of students in the class = 20 First, we will make a tree diagram like this: Part a Draw a tree diagram and find the probability that:Ĭ) Two girls and 1 boy is selected Solution If a teacher selects a group of 3 at random. In a class, there are eight boys and 12 girls.
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